Proszę uprzejmie o pomoc z matematyki. Rozwiąż układ równań metodą przeciwnych współczynników:
\left \{ {{y= (2x - 1)^{2} - (2x + 3)^{2} } \atop {(2y - 1) (2y + 1) + 96 = 4y (y+3) + x}} \right. [tex]\left \{ {{y= (2x - 1)^{2} - (2x + 3)^{2} } \atop {(2y - 1) (2y + 1) + 96 = 4y (y+3) + x}} \right.[/tex]
\left \{ {{y= (2x - 1)^{2} - (2x + 3)^{2} } \atop {(2y - 1) (2y + 1) + 96 = 4y (y+3) + x}} \right. [tex]\left \{ {{y= (2x - 1)^{2} - (2x + 3)^{2} } \atop {(2y - 1) (2y + 1) + 96 = 4y (y+3) + x}} \right.[/tex]
[tex]\left \{ {{y=(2x-1)^{2 }-(2x+3)^{2} } \atop {(2y-1)(2y+1)+96=4y(y+3)+x}} \right. \\\\\left \{ {{y=4x^{2} -4x+1-4x^{2} -12x-9} \atop {4y^{2}-1+96=4y^{2}+12y+x }} \right.\\ \\\left \{ {{y=-16x-8} \atop {95=12y+x}} \right. \\\\\left \{ {{16x+y=-8/*12} \atop {-x-12y=-95}} \right. \\\\\left \{ {{192x+12y=96} \atop {-x-12y=-95}} \right. \\\\191x=1\\\\x=\frac{1}{191}\\ \\y=-16*\frac{1}{191}-8=-\frac{16}{191}-\frac{1528}{191}=-\frac{1544}{191}[/tex]