Odpowiedź:
[tex]\displaystyle \frac{\sqrt{3}-1/\cdot(2\sqrt{6} +3)} {2\sqrt{6} -3/\cdot(2\sqrt{6} +3)}=\\\frac{2\sqrt{18} +3\sqrt{3}-2\sqrt{6} -3 }{24-9} =\frac{6\sqrt{2} +3\sqrt{3}-2\sqrt{6}-3 }{15}[/tex]
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Verified answer
Odpowiedź:
[tex]\displaystyle \frac{\sqrt{3}-1/\cdot(2\sqrt{6} +3)} {2\sqrt{6} -3/\cdot(2\sqrt{6} +3)}=\\\frac{2\sqrt{18} +3\sqrt{3}-2\sqrt{6} -3 }{24-9} =\frac{6\sqrt{2} +3\sqrt{3}-2\sqrt{6}-3 }{15}[/tex]