Question

Tentukan Nilai X
a. 2x - 1 ≥ 4x + 3
b. [tex] \frac{x - 1}{3} = \frac{2x + 1}{2} [/tex]​

Answer 1

Bagian A :

2x - 1 ≥ 4x + 3

2x - 4x ≥ 3 + 1

-2x ≥ 3 + 1

-2x ≥ 4

x ≤ -4/2

x ≤ -2

Bagian B :

(x - 1)/3 = (2x + 1)/2

(x - 1)(6)/3 = (2x + 1)(6)/2

2(x - 1) = 3(2x + 1)

2x - 2 = 6x + 3

2x - 6x = 3 + 2

-4x = 3 + 2

-4x = 5

x = -5/4