Question

tolong ya kak
[tex] \frac{ \sqrt{32} - \sqrt{8} + 3 \sqrt{2} }{ \sqrt{2} } [/tex]
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Answer 1

• [tex]\frac{\sqrt{32} - \sqrt{8} + 3 \sqrt{2}}{\sqrt{2}} = \frac{\sqrt{16 \times 2} - \sqrt{4 \times 2} + 3 \sqrt{2}}{\sqrt{2}} [/tex]
• [tex]= \frac{4 \sqrt{2} - 2 \sqrt{2} + 3 \sqrt{2}}{\sqrt{2}} [/tex]
• [tex]= \frac{(4 - 2 + 3) \sqrt{2}}{\sqrt{2}} = \frac{5 \sqrt{2}}{\sqrt{2}} = 5[/tex]