Question

[tex]3^{2x+3}=\sqrt[3]{27^{x+5} }\\\\x=...[/tex]

Answer 1

Verified answer

Jawab:

2

Penjelasan dengan langkah-langkah:

[tex]3^{2x+3} = \sqrt[3]{27^{x+5} }\\ \\3^{2x+3} = 27^{\frac{x+5}{3} } \\\\3^{2x+3} = (3^{3} )^{\frac{x+5}{3} } \\\\3^{2x+3} = 3^{x+5} \\\\2x + 3 = x+5\\\\2x-x =5-3\\\\x=2[/tex]

Answer 2

[tex]\sf \bf \sf 3^{2x+3}=\sqrt[3]{27^{x+5} }[/tex]

[tex]\sf \bf \sf 3^{2x+3}=27^{\frac{x+5}{3}}[/tex]

[tex]\sf \bf \sf 3^{2x+3}=3^{(3)\frac{x+5}{3}}[/tex]

[tex]\sf \bf \sf 3^{2x+3}=3^{(\cancel{3})\frac{x+5}{\cancel{3}}}[/tex]

[tex]\sf \bf \sf 3^{2x+3}=3^{x+5}[/tex]

[tex]\sf \bf \sf \cancel{3}^{2x+3}=\cancel{3}^{x+5}[/tex]

[tex]\sf \bf \sf {2x+3}={x+5}[/tex]

[tex]\sf \bf \sf {2x-x}={5-3}[/tex]

[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt x = 2}}}}[/tex]

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