Question

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[tex] {3}^{9 {}^{x - 2 \: } } = 27 {}^{9 {}^{2x + 1} } [/tex]
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Answer 1

Verified answer

[tex] \\ {3}^{9 ^{x - 2} } = {27}^{9 ^{2x + 1}} [/tex]

[tex] \\ {9}^{x - 2} = {3}^{4x + 3} [/tex]

[tex] \\ 2x - 4 = 4x + 3[/tex]

[tex] \\ 2x - 4x = 3 + 4[/tex]

[tex] \\ - 2x = 7[/tex]

[tex] \\ x = - \frac{7}{2} [/tex]

✓