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1. dalam deret geometri, U2 = 6 dan U3 = 9, maka 16 U_{7} [/tex] =
2.dalam deret geometri, U7 = 192 dan U2 = 6, maka U9 =
3.  \frac{1}{12}, \frac{1}{6}, \frac{1}{3}, \frac{2}{3} , ......, maka 6 U_{13}
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