Question

Tersedia kawat 2m .apabila di buat kerangka balok yg berukuran 18cm x 12cm x 9cm,maka sisa kawat yg tak terpakai adalah...

Answer 1

Kawat = 2 m
          = 200 cm

p = 18 cm

l = 12 cm

t = 9 cm

Rusuk = 4(p + l + t)
          = 4(18 + 12 + 9)
          = 4(39)
          = 156 cm

Sisa = Kawat - Rusuk
        = 200 cm - 156 cm
        = 44 cm

Answer 2

JUMLAH RUSUK = 4X(P + L + T)
= 4 X (18 + 12 + 9)
= 4 X 39
= 156
2 METER = 200 CM
SISA = 200 - 156 = 44 CM