Question

Terdapat 500 ml CH3COONa 0,002 M (Ka CH3COONa = 2X 10-5). Tentukan pH larutan garam tersebut.

Answer 1

Diket : V=500 ml
          MCH₃COONa = 0,002 M
          Ka = 2×10⁻⁵
ditanya : PH larutan garam .... ?
jawab : {H⁺} = Ka × na/ng
                  = 2×10⁻⁵ × 1/1
              PH= 5 - log 2