Question

Tentukn massa molekul relatif senyawa berikut:
a. CaCO3
b. NaHCO3
c. MgSO4
d. Na2HPO4
e. KNO3

Answer 1

A. Mr CaCO₃ = Ar Ca + Ar C + 3.Ar O = 40 + 12 + 3.16 = 40 + 12 + 48 = 100 g/mol

b. Mr NaHCO₃ = Ar Na + Ar H + Ar C + 3.Ar O = 23 + 1 + 12 + 48 = 84 g/mol

c. Mr MgSO₄ = Ar Mg + Ar S + 4.Ar O = 24 + 32 + 64 = 120 g/mol

d. Mr Na₂HPO₄ = 2.Ar Na + Ar H + Ar P + 4.Ar O = 46 + 1 + 31 + 64 = 142 g/mol

e. Mr KNO₃ = Ar K + Ar N + 3.Ar O = 39 + 14 + 48 = 101 g/mol

Answer 2

A.
Ca=40
C=12
O=16 x 3=48
Total = 100
B.
Na=23
H=1
C=12
O=16 x3=48
Total= 84
C.
Mg= 24
S=32
O=16x4=64
Total = 120
D.
Na=23 x2 = 56
H=1
P=31
O=16 x4= 64
Total = 152
E.
K=39
N=14
O=16x3=48
Total = 101