Question

Tentukanlah nilai a dan b, jika: -3x^3 + 14x^2 + ax + b dibagi (-x^2 + 4x - 1) & sisanya (6x-7). Tlong dibantu yah...

Answer 1

Cara honer
-(3x³ - 14x² - ax - b) : - (x² - 4x +1) = 
  
....  3......-14.......-a......-b
-1........................-3......2
4............12.........-8.........
......3.......-2........-a-11...-b+2
-a-11 = 6 --> a = -17
-b+2 = -7 --> b =  9
.
a = -17 dan b = 9