tentukanlah hasil dari:
1. (7x-2)²
2. (2x-7) (3x+4)
3. (2y²+y)²
1. (7x-2)²
2. (2x-7) (3x+4)
3. (2y²+y)²
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Jawab:
1.(7x-2)²
= (7x-2) (7x-2)
= 49x² - 14x - 14x + 4
= 49x² - 28x + 4
2.(2x-7) (3x+4)
= 6x² + 8x - 21x - 28
= 6x² - 13x - 28
3.(2y²+y)²
= (2y²+y) (2y²+y)
= 4y⁴ + 2y³ + 2y³ + y²
= 4y⁴ + 4y³ + y²
Jawaban:
1. 49x²-28x+4
2. 6x²-13x+28
3. 4y⁴+4y⁴+y²