Question

Tentukanlah akar-akar persamaan dari:
• 4x²-x-5=0
• x²+12x+27=0

tolong bantu jawab soal uh ak yg kmrn kak, bwt dipelajari lg soalnya hehe makasi​

Answer 1

1. 4x^2 - x - 5 = 0

a = 4 | b = -1 | c = -5

a × c = -20 | b = -1

-5 × 4 = -20

-5 + 4 = -1

(x - 5)(x + 4)

x = 5 | x = -4

2. x^2 + 12x + 27 = 0

a = 1 | b = 12 | c = 27

a × c = 27 | b = 12

9 × 3 = 27

9 + 3 = 12

(x + 9)(x + 3)

x = -9 | x = -3