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√(2x-5)² = √(x-2)²
kuadratkan kedua ruas, get
(2x-5)² = (x-2)²
(2x-5)² - (x-2)² = 0
(2x-5+x-2)(2x-5-(x-2)) = 0
(3x -7)(x - 3) = 0
pembuat nol :
3x- 7 = 0
3x = 7
x = 7/3
x - 3 = 0
x = 3
solusi = {7/3 , 3}
√(2x-5)² = √(x-2)²
kuadratkan kedua ruas, get
(2x-5)² = (x-2)²
(2x-5)² - (x-2)² = 0
(2x-5+x-2)(2x-5-(x-2)) = 0
(3x -7)(x - 3) = 0
pembuat nol :
3x- 7 = 0
3x = 7
x = 7/3
x - 3 = 0
x = 3
solusi = {7/3 , 3}