Question

tentukan turunan masing masing fungsi aljabar berikut . f(x) =8x²-4x²+x-5​

Answer 1

Jawaban:

f'(x) = 8x + 1

Penjelasan dengan langkah-langkah:

f(x) = 8x² - 4x² + x - 5

= 4x² + x - 5

f'(x) = 2 . 4x^(2-1) + 1 . x^(1-1) - 0 . 5x^(0-1)

= 8x + 1 - 0

= 8x + 1

#LearnWithPanda

Answer 2

Jawab:

f(x) =8x²-4x²+x-5​

turunan: f'(x) = 8x + 1

Penjelasan dengan langkah-langkah:

Turunan fungsi:

[tex]\boxed{f'(x) = a.n.x^{n-1} }[/tex]

a = koefisien

n = pangkat

---

f(x) = 8x² - 4x² + x - 5

f(x) = 4x² + x - 5

---

4x² = 4.2.x²⁻¹ = 8.x¹ = 8x

x = 1x¹ = 1.1.x¹⁻¹ = 1.x⁰ = 1

5 = 5.x⁰ = 5.0.x⁰⁻¹ = 0.x⁻¹ = 0

Maka:

f(x) = 8x² - 4x² + x - 5

f(x) = 4x² + x - 5

f'(x) = 8x + 1 - 0

f'(x) = 8x + 1