Penjelasan dengan langkah-langkah:
FungSi
f(x) = x³+2x²
turunan ke-3
.
f'(x) = 3x²+2(2x¹)
f'(x) = 3x²+4x
f''(x) = 3(2x) + 4
f''(x) = 6x + 4
f'''(x) = 6(x⁰) + 0(4)
f'''(x) = 6 ✓
Jawaban:
f"'(x) = 6 dx
[tex]f(x) = {x}^{3} + 2{x}^{2} \\ {f}^{1} (x) = 3 {x}^{2} + 2x \: \: \: dx\\ {f}^{11} (x) =6 x + 2 \: \: \: dx \\ {f}^{111} (x) = 6 \: \: \: \: dx[/tex]
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Penjelasan dengan langkah-langkah:
FungSi
f(x) = x³+2x²
turunan ke-3
.
f(x) = x³+2x²
f'(x) = 3x²+2(2x¹)
f'(x) = 3x²+4x
f''(x) = 3(2x) + 4
f''(x) = 6x + 4
f'''(x) = 6(x⁰) + 0(4)
f'''(x) = 6 ✓
Jawaban:
f"'(x) = 6 dx
Penjelasan dengan langkah-langkah:
[tex]f(x) = {x}^{3} + 2{x}^{2} \\ {f}^{1} (x) = 3 {x}^{2} + 2x \: \: \: dx\\ {f}^{11} (x) =6 x + 2 \: \: \: dx \\ {f}^{111} (x) = 6 \: \: \: \: dx[/tex]