Tentukan turunan ke 1 dan ke 2 dari fungsi a.f(x)= b.f(x)=.... Question from @noneka

Takamori37 A.
$f(x)=\frac{3}{32}x^5-\frac{20}{32}x^3=\frac{3}{32}x^5-\frac{5}{8}x^3 \\ $Turunan ke-1$ \\ f'(x)=\frac{3}{32}\times 5x^4-\frac{5}{8}\times 3x^2 \\ \boxed{f'(x)=\frac{15}{32}x^4-\frac{15}{8}x^2} \\\\ $Turunan ke-2$ \\ f''(x)=\frac{15}{32}\times 4x^3-\frac{15}{8}\times 2x \\ \boxed{f''(x)=\frac{15}{8}x^3-\frac{15}{4}x}$

b.
$f(x)=5x^{2/3}-x^{5/3} \\ f'(x)=5\times\frac{2}{3}x^{2/3-1}-\frac{5}{3}x^{5/3-1} \\ \boxed{f'(x)=\frac{10}{3}x^{-1/3}-\frac{5}{3}x^{2/3}} \\\\ f''(x)=\frac{10}{3}\times\frac{-1}{3}x^{-4/3}-\frac{5}{3}\times\frac{2}{3}x^{-1/3} \\ \boxed{f''(x)=-\frac{10}{9}x^{-4/3}-\frac{10}{3}x^{-1/3}}$

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alvinteguh A. $f(x) = \frac{3}{32} x^{5} - \frac{20}{32} x^{3} \\Turunan 1 f'(x) = \frac{3}{32} .5 x^{4} - \frac{5}{8} .3 x^{2} \\ f'(x) = \frac{15}{32} x^{4} - \frac{15}{8} x^{2} \\ Turunan 2 f''(x) = \frac{15}{32}.4 x^{3} - \frac{15}{8} .2x \\ f''(x) = \frac{15}{8} x^{3} - \frac{15}{4} x
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b. $f(x) = 5 x^{2/3} - x^{5/3} \\ Turunan 1 f'(x) = 5. \frac{2}{3} x^{-1/3} - \frac{5}{3} . x^{2/3} \\ f'(x) = \frac{10}{3} x^{-1/3} - \frac{5}{3} x^{2/3} \\ Turunan 2 f''(x) = \frac{10}{3} . \frac{-1}{3} x^{-4/3} - \frac{5}{3} . \frac{2}{3} x^{-1/3} \\ f''(x) = - \frac{10}{9} x^{-4/3} - \frac{10}{9} x^{-1/3}$

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Carilah Solusi sistem persamaan linier dengan menggunakan eliminasi gauss jordan 2x+2y+2z=0 -2x+5y+2z=1 8z+y+4z=1

Tentukan turunan pertama dari f(x)=

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Bentuk sederhana dari (5/6+1/3)^-2

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