Question

Tentukan titik stationer f(x)= x² - 8x² - 9

Answer 1

F(x) = x² - 8x - 9
f'(x) = 0
2x - 8 = 0
2x = 4
x = 2

f(2) = 2² - 8(2) - 9
       = 4 - 16 - 9
       = -21
 titik stasioner (2,-21) jenisnya titik balik maksimum