f(x) = ax+b
f(f(x)) =a(ax+b)+b= x
a²x+ab+b= x
a²=1
a1=1; a2=-1
ab+b=0
b(a+1)=0
b1(1+1)=0
b1=0
b2(-1+1)=0
b2={b|b anggota R}
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f(x) = ax+b
f(f(x)) =a(ax+b)+b= x
a²x+ab+b= x
a²=1
a1=1; a2=-1
ab+b=0
b(a+1)=0
b1(1+1)=0
b1=0
b2(-1+1)=0
b2={b|b anggota R}