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kalor jenisnya abaikan sja krn sma" air, artinya tinggal
300 . (x - 20) = 200 . (80 - x)
3 (x - 20) = 2 (80-x)
-60 + 3x = 160 - 2x
-60 - 160 = -3x - 2x
- 220 = -5x
44 = x
artinya suhu campurannya yaitu 44 derajat celcius
m2.c2.Δt2 = m1.c1.Δt1
200.1.(80-ta) = 300.1.(ta-20)
16000 - 200ta = 300ta - 6000
22000 = 500ta
ta = 44 derajat C