" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
X' = -2
Gunakan rumus :
x(Y') + y(X') = X'Y'
x(3) + y(-2) = (3)×(-2)
3x - 2y = -6
2y = 3x + 6
y = (3/2)x + 3
atau
(-2,0) & (0,3)
x1 = -2
y1 = 0
x2 = 0
y2 = 3
Rumus :
(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-0)/(3-0) = (x-[-2])/(0-[-2])
y/3 = (x+2)/2
2y = 3(x+2)
2y = 3x + 6
y = (3x/2) + 6/2
y = (3/2)x + 3