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Katoda : 2H2O + 2e- ==> 2OH- + H2 x2
Anoda : 2H2O ==> 4H+ + O2 + 4e- x1
tujuanny dikali, agar jumlah elektronnya sama.
Katoda : 4H2O + 4e- ==> 4OH- + 2H2
Anoda : 2H2O ==> 4H+ + O2 + 4e-
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reaksi : 6H2O ==> 4OH- + 2H2 + 4 H+ + O2 ( 4H+ + 4OH- = 4H2O )
maka reaksi : 6H2O ==> 4H2O + 2H2 + O2
= 2H2O ==> 2H2 + O2
jangan lupa bintangnya ya...hee