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20 mL KOH 0,1 M = 2 mmol
50 mL CH₃COOH 0,05 M = 2,5 mmol
KOH + CH₃COOH ⇒ CH₃COOK + H₂O
Awal : 2 2,5
Reaksi : 2,5 2,5 2,5
Sisa : 0,5 - 2,5
[H⁺] = Ka · [ mol asam / mol basa ]
[H⁺] = 10⁻⁵ [ 2,5 / 0,5 ]
[H⁺] = 10⁻⁵ · 5
[H⁺] = 5 · 10⁻⁵
Maka, pH yaitu
pH = - log [H⁺]
pH = - log [5 · 10⁻⁵]
pH = - log 5 - log 10⁻⁵
pH = 5 + - log 5