Question

Tentukan ph larutan ca(oh)2 0,1M dengan kw = 10^-12

Answer 1

OH-=akar Kb×M
OH-=akar 1×10^-12 × 1×10^-1
OH-=akar 1×10^-13
OH-=akar 1/10×10^-12
OH-=akar 0.1×10^-12
OH-=0.3×10^-6
skrg cari pOH lalu pH
pOH=-log(0.3×10^-6)
pOH=6-log0.3
pH=14-(6-log0.3)
pH=8+log0.3
pH=8+(-0.5)
pH=7.5

semoga membantu