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Verified answer
NaOH 0,03 M[OH-] = b . M
= 1 . 0,03
= 0,03
pOH = - log [OH-]
= - log [3 x 10^-2]
= 2 - log 3
= 2 - 0,47
= 1,53
pH = 14 - pOH
= 14 - 1,53
= 12,47