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n CH3COONa = 0.5 * 0.2 = 0.1
[H+] = Ka * na/nbk = 1.8 x 10^-5 * 0.5/0.2 =1.8 x 10^-5 * 5
= 9 x 10^-5
pH = - log [H+]
= - log ( 9 x 10^-5)
= 5 - log 9