Tentukan pertidaksamaan dari nilai mutlak 1. 0 < |x-3| ≤ 32. |2x+1| < |2x-3|3. |x-17| ≤ |7x-5|.... Question from @TheresiaCeline

April 2019 1 24 Report

Tentukan pertidaksamaan dari nilai mutlak
1. 0 < |x-3| ≤ 3
2. |2x+1| < |2x-3|
3. |x-17| ≤ |7x-5|

nabnabs 1. |x-3|<=3
-3<=x-3<=3
0<=x<=6

2. |2x+1|<|2x-3|
(2x+1)^2<(2x-3)^2
4x^2 + 4x +1 < 4x^2 -12x +9
16x<8
x<2

3. |x-17|<=|7x-5|
(x-17)^2<=(7x-5)^2
x^2-34x+289<=49x^2-70x+25
48x^2-36x-264>=0
12x^2-9x-66>=0
(x+2)(12x-33)>=0
x<=-2 atau x>=33/12

1 votes Thanks 1

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Tentukan penyelesaian dari pertidaksamaan nilai mutlak berikut:1. |2x-3| < 72. |3x+2| > 5ps: tolong bantuin yaa yang baik.. soalnya buat ntar

Answer

1. Jika f(x) = 3x²-1 dan g(x) = 2x-1/x+2 , tentukan nilai (fog) (3)!2. Jika f(x) = (2x+1)³-4 dan g(x) = ½ ³√x+4+½ , tentukan nilai (gof) (2)!3. Misal f(x) = x-5 dan g(x) = x²+2x+1 , tentukan nilai (gof) (4)!PS: no. 1 itu / artinya per. No. 2 itu akar pangkat 3

Tentukan penyelesaian dari pertidaksamaan nilai mutlak berikut:1. |2x-3| < 72. |3x+2| > 5ps: tolong bantuin yaa yang baik.. soalnya buat ntar

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