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Verified answer
Jawabtitik pusat (a ,b)
(a,b) = 1/2 {(-4 + 2) , (5 +3)} = 1/2 ( -2, 8)
(a,b) = (-1. 4)
r = jarak (-1, 4) ke p(- 4, 5)
persamaan lingkaran (x - a)^2 + (y -b)^2 = r^2
(x + 1)^2 + (y - 5)^2 = (-1+4)^2 +(4 - 5)^2
x^2 + 2x + 1 + y^2 -10y +25 = 9 + 1
x^2 + y^2 + 2x -10y +16= 0