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a = 3 dan b = -5
gradien (m) sejajar
= - a/b
= - 3/(-5)
= 3/5
maka,
pers. grs. melalui ttk.(3,4) dan m = 3/5
adalah :
y-y1 = m(x-x1)
y-4 = 3/5 (x-3)
kedua ruas dikalikan dg 5, menjadi :
5(y-4) = 3(x-3)
5y-20 = 3x-9
3x-5y-9+20 = 0
3x-5y+11 = 0
atau
3x-5y = -11