Question

Tentukan persamaan garis yg melalui titik(2,-3) dan tegak lurus garis 2x+3y-5=0

Answer 1

Melalui (2,-3) tegak lurus 2x+3y-5=0
2x + 3y - 5 = 0
m1 = 2
m1.m2 = 4
2.m2 = 4
m2 = 4:2
m2 = 2
m2 = 2 ⇒ (2,-3)
y-y1 = m(x-x1)
y-(-3) = 2(x-2)
y+3 = 2x-4
    y = 2x-4-3
    y = 2x-7

Answer 2

2x+3y-5=0
-(2/3) = -2/3
m2 = 1 1/2

persamaan
y-y1=m(x-x1)
y-(-3) = 1 1/2 (x-2)
y+ 3 = 1 1/2x - 3
y - 1 1/2× = -3 -3
y - 1 1/2x = -6

jadikanlah sebagai jawaban terbaik :)