Question

Tentukan persamaan garis yang tegak lurus x-5y=10 dan melalui titik (2,-4)

Answer 1

Persamaan = x - 5y = 10
= x - 5y - 10 = 0
m1 = -a/b = -1/-5 = 1/5

Syarat = m1 × m2 = - 1
1/5 × m2 = -1
m2 = -1 : 1/5
m2 = -1 × 5/1
m2 = -5/1
m2 = -5

Rumus

y - y1 = m ( x - x1 )
y - (-4) = -5 ( x - 2 )
y + 4 = -5x + 10
y = -5x + 10 - 4
y = -5x + 6
5x + y - 6 = 0