Question

Tentukan persamaan garis yang tegak lurus 2x-5y=8 melalui (7,2)

Answer 1

2x-5y = 8
m=-a/b
   = -2/-5
   = 2/5
Tegak lurus : m1.m2 = -1
                    m = -5/2

y-y1 = m( x-x1)
y-2 = -5/2 ( x-7)
2y-4 = -5 ( x-7)
2y- 4 = -5x+35
2y = -5x + 39
y = -5x + 39 /2

Answer 2

2x - 5y = 8
m1 = 2
m2 = ? (m1.m2= (-1))
m1.m2= -1
2.m2= -1
m2 = -1/2

y-y1 = m(x-x1)
y-2 = -1/2(x-7)
y-2= -1/2x+7
y = -1/2x+2+7
y = -1/2x+9

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