Question

Tentukan persamaan garis yang melewati titik A (-7,3) bergradien -4

Answer 1

A=(-7,3)
x₁=-7
y₁=3

y-y₁=m(x-x₁)
y-3 =-4(x-(-7))
y    =-4x-28+3
y    =-4x-25

Answer 2

M(x-x1) = y-y1
-4 (x-(-7)) = y-3
-4x -4.7 = y-3
-4x -28 = y-3
-4x -28 -y +3 = y -y -3 +3
-4x -y -28 +3 = 0
-4x -y -25 = 0