Question

Tentukan persamaan garis yang melalui titika(1,3) dan b(4,6)

Answer 1

M = (y2-y1) / (x2-x1)
m = (6-3) / (4-1) = 1

y-y1 = m(x-x1)
y-3 = 1(x-1)
y-3 = x-1
y = x+2

Answer 2

(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-3)/(6-3) = (x-1)/(4-1)
(y-3) / 3 = (x-1) / 3
3(y - 3) = 3(x - 1)
3y - 9 = 3x - 3
3y - 3x = -3 + 9
3y - 3x = 6