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m1=-a/b=-2/1=-2
tegak lurus m2=-1/m1=-1/-2=1/2
jd persamaan garis yg melalui (0,0)
y-y1=m(x-x1)
y-0=1/2(x-0)
y=1/2x
y=-2x+4
m=-2
y-y1=m(x-x1)
y-0=-2(x-0)
y=-2x
2x+y=0