Question

Tentukan persamaan garis yang melalui titik M(-2,6) dan N(4,-3).

Answer 1

M(x1,y1)= (-2,6)
N(x1.y2) = (4, -3)
Garis MN  ⇒ (x2-x1)(y-y1) = (y2-y1)(x-x1)
{4 - (-2)} (y - 6) = (-3-6){ x - (-2)}
6(y-6) = -9( x+2)
6y - 36 = -9x - 18
6y + 9x = 18
 atau
3x + 2y  = 6
3x + 2y - 6 = 0

Answer 2

(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y - 6)/(-3 - 6) = (x - (-2))/(4 - (-2))
(y - 6)/-9 = (x + 2)/6
6(y - 6) = -9(x + 2)
6y - 36 = -9x - 18
9x + 6y - 36 + 18 = 0
9x + 6y - 18 = 0
3 (3x + 2y - 6) = 0
3x + 2y - 6 = 0