Question

tentukan persamaan garis yang melalui titik k(-2,8) dan l(0,6)​

Answer 1

[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \\ \frac{y - 8}{6 - 8} = \frac{x - ( - 2)}{0 - ( - 2)} \\ \\ \frac{y - 8}{ - 2} = \frac{x + 2}{2} \\ \\ 2(y - 8) = - 2(x + 2) \\ 2y - 16 = - 2x - 4 \\ 2y + 2x - 16 + 4 = 0 \\ 2x + 2y - 12 = 0 \\ - - - - - - - - \div 2 \\ x + y - 6 = 0[/tex]