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sejajar garis 2x+3y-1=0 diubah menjadi 3y=-2x+1
y=-2/3
x1= -3 y1= 2
m1= -2/3, maka m2= -2/3
y-y1= m2(x-x1)
y-2= -2/3(x-(-3)
y-2= -2/3(x+3)
y-2= -2/3x-2
y=-2/3x-2+2
y=-2/3x+0
y=-2/3x
3y=-2x
y-y1 = m(x-x1)
y-2=-2(x-(-3))
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3
3(y-2)=-2x+6
3y-6=-2x+6
3y=-2x+12