Question

Tentukan persamaan garis singgung parabola y^2+6y-8x+25=0 tegak lurus garis 2x+y-3=0

Answer 1

Y^2 + 6y - 8x + 25 = 0
(y+3)^2 = 8x -25 + 9
(y+3)^2 = 8x - 16 = 8(x-2)
a= 2, b = -3 , 4p= 8 -->p = 2
tegaklurus 2x+y -3 = 0 --> m1 = -2
m2 = 1/2
.
Pers. gasing-->
y = b + m(x-a) + p/m
y = -3 +1/2(x-2) + 2/(1/2)
y = -3 + 1/2 x  - 1 +4
y = 1/2 x --> 2y = x
atau  x - 2y = 0