Question

Tentukan persamaan garis melalui titik (-2,6) (4,-3)

Answer 1

M = (-3-6) ÷ (4+2) = 9÷6 = 3/2

persamaan garis
y - y1 = m ( x -x1 )
y - 6 = 3/2 ( x + 2)
y - 6 = 3/2x + 3
y = 3/2x +9

Answer 2

y-y1 = x-x1
y2-y1=x2-x1
x1=-2
y1=6
x2=4
y2=-3
y-6 = x-(-2)
-3-6  4-2
y-6 = x-(-2)
-9      2
2(y-6) = -9(x-(-2))
2y - 12 = -9x - 18
9x+2y-12+18 =0
9x+2y+6 =0