Question

Tentukan persamaan garis melalui titik (-1,6) dan (8,3)

Answer 1

(y-y1)/(y2-y1)=(x-x1)/(x2-x1)
(y-6)/(3-6)=(x+1)/(8+1)
(y-6)/(-2)=(x+1)/(9)
9y-54=-2x-2
2x+9y-52=0

Answer 2

(-1,6) (8,3)
y - y1 / y2-y1 = x - x1/ x2-x1
y - 6 / 3 - 6 = x + 1 / 8 + 1
y - 6 / -3 = x +1 / 9
9 (y - 6 ) = -3 ( x + 1)
9y - 54 = -3x - 3  | :3
3y - 18 = -x -1
x +3y -17 = 0