Question

Tentukan persamaan garis melalui (4,10)
a. Sejajar garis y= -3x + 5
b. Tegak lurus y=-3x + 5



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Answer 1

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Persamaan Garis

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Melalui (4,10)
a][
sejajar y = -3x + 5
m1 = -3

krn sejajar, m2 = m1 = -3

Pers garis mlalui (x1,y1) = (4,10) dan m = -3 :
y - y1 = m(x - x1)
y - 10 = -3(x - 4)
y = -3x + 12 + 10
y = -3x + 22 ✔

b][
tegaklurus y = -3x + 5
m1 = -3

Tegaklurus ---> m2 = -1/m1 = 1/3

Pers garis mlalui (4,10) dan m = 1/3 :
y - y1 = m(x - x1)
y - 10 = 1/3 (x - 4)
3y - 30 = x - 4
3y = x - 4 + 30
y = (x + 26)/3
y = 1/3 x + 26/3 ✔