Tentukan persamaan garis lurus yang sejajar dengan garis 12x + 3y + 6 = 0 dan melalui titik (3, 5)!
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[tex]sejajar \\ 12x + 3y = 12(3) + 3(5) \\ 12x + 3y = 36 + 15 \\ 12x + 3y = 51 \\ 12x + 3y - 51 = 0 \\ - - - - - - - - - \div 3 \\ 4x + y - 17 = 0[/tex]