Question

Tentukan persamaan garis lurus yang melalui titik A (-1,-4) dan B (2,6)




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Answer 1

Y-y1 / y2-y1 = x-x1 / x2-x1
y-(-4) /6-(-4) = x-(-1) / 2-(-1)
y + 4 / 10 = x+1 / 3
3(y+4) = 10(x+1)
3y + 12 = 10x + 10
-10x + 3y + 2 = 0
10x -3y - 2 = 0