Tentukan persamaan garis lurus yang melalui titik (-2, 3) dan tegak lurus dengan garis 3x+6y=
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PErSAmaan Garis
Tegak lurus
garis tegak lurus dengan garis 3 x+ 6y= c
melalui (- 2, 3) adl
6x - 3y = 6(-2) - 3(3)
6x - 3y = -12 - 6
6x - 3y = -18
ax + by + c = 0
maka :
3x + 6y = 6(-2) - 3(3)
3x + 6y = -(6.2) - (3.3)
3x + 6y = -12 - 9
3x + 6y = -18