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(y-y1)/(y2-y1) = (x-x1) / (x2-x1)
a. (y-0) / (5-0) = (x-0) / (4-0)
y/5 = x/4
y = 5x/4 atau 5x-4y=0
b. (y-5)/(8-5) = (x+2)/(4+2)
(y-5)/3 = (x+2)/6
6y-30 = 3x+6
6y = 3x + 36 (msg-msg dibagi 3)
2y = x + 12 atau x-2y = -12
(1.y-0)/(5-0)=(x-0)/(4-0)
y/5=x/4
4y=5x
5x-4y=0
2.(y-5)/(8-5)=(x+2)/(4+2)
(y-5)/3=(x+2)/6
2y-10=x+2
2y-10-x-2=0
2y-x-12=0
2y-x=12