Question

Tentukan persamaan fungsi kuadrat melalui titik (6,0), (-3,0) , dan (3,18)
mohon bantuannya :'>

Answer 1

Verified answer

Kelas 10 Matematika
Bab Fungsi Kuadrat

y = a (x - x1) . (x - x2)
18 = a . (3 - 6) . (3 - (-3))
18 = a . (-3) . 6
a = 18/-18
a = -1

y = (-1) . (x - x1) . (x - x2)
y = (-1) . (x - 6) . (x + 3)
y = (-1) . (x² - 3x - 18)
y = -x² + 3x + 18