Question

Tentukan persamaan elips dengan pusat (0,0), fokus (4,0), dan (-4,0) serta panjang sumbu mayor 12.

Answer 1

Puncak mayor elips = 12/2 = 6 =a
puncak minor elips = b = √ (a^2 - c^2)
B= √36-16 = √20
k= 0
h= 6
(y-k)^2/b^2 + (x-h) ^2/a^2 = 1
k & h bernilai 0 karena Ps= (0,0)
y^2/20 + x^2/36 = 1