Question

Tentukan Pers Garis Yg Melalui Titik (-12,-18) Dan Tegak Lurus Dg Garis Yg Persamaannya Sbg Berikut
a.8y=6x + 16
b.4x-6y+12=0

Answer 1

(-12,-18)
a. 8y = 6x + 16
--------------------- ÷8
y =3/4x + 2
m1 = 3/4
tegak lurus <=> m1 . m2 = -1
3/4 . m2 = -1
m2 = -4/3

y - y1 = m(x - x1)
y - (-18) = -4/3 (x - (-12))
y + 18 = -4/3x - 16
y = -4/3x - 34
atau
4/3x + y + 34 = 0

b. 4x - 6y + 12 = 0
-a/b -> -4/-6
m1 = 2/3
tegak lurus = m1 . m2 = -1
2/3 . m2 = -1
m2 = -3/2

y - y1 = m (x - x1)
y - (-18) = -3/2 (x -(-12))
y + 18 = -3/2x - 18
y = -3/2x - 36
atau
3/2x + y + 36 = 0

maaf kalo salah._.