Tentukan penyelesaian dengan persamaan kuadrat. 1. x^2 = 18 - 3x 2. 3x^2 + 6 = 11x 3. 2

September 2018 2 109 Report

Tentukan penyelesaian dengan persamaan kuadrat.
1. x^2 = 18 - 3x
2. 3x^2 + 6 = 11x
3. 2 - 9x = -10x^2

whongaliem No.1 ) x² = 18 - 3x
x² + 3x - 18 = 0
(x - 3)(x + 6) = 0
x = 3 atau x = - 6
Hp = { - 6 , 3}
no.2)...3x² + 6 = 11x
3x² - 11x + 6 = 0
(3x - 2)(x - 3) = 0
3x - 2 = 0 atau x - 3 = 0
3x = 2 atau x = 3
x = 2/3
Hp = { 2/3 , 3}
no.3) ..2 - 9x = - 10x²
10x² - 9x + 2 = 0
(5x - 2)(2x - 1) = 0
5x - 2 = 0 atau 2x - 1 = 0
5x = 2 atau 2x = 1
x = 2/5 atau x = 1/2
Hp = { 2/5 . 1/2}

2 votes Thanks 1

Mausuf 1. $x^2=18-3x$
$x^2+3x-18=0$
$(x+6)(x-3)=0$
$x=-6$ atau $x=3$
2. $3x^2+6=11x$
$3x^2-11x+6=0$
$(3x-2)(x-3)=0$
$x= \frac{2}{3}$ atau $x=3$
3. $2-9x=-10x^2$
$10x^2-9x+2=0$
$(5x-2)(2x-1)=0$
$x= \frac{2}{5}$ atau $x= \frac{1}{2}$

1 votes Thanks 1

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